From 1a0ebe6152e5e4d91eed9bafd7db2f294fd889a4 Mon Sep 17 00:00:00 2001 From: Bruce Momjian <bruce@momjian.us> Date: Wed, 3 Jun 2009 14:48:33 +0000 Subject: [PATCH] Add comment about why "((void) 0)" is used in copy macros. --- src/backend/commands/copy.c | 5 +++-- 1 file changed, 3 insertions(+), 2 deletions(-) diff --git a/src/backend/commands/copy.c b/src/backend/commands/copy.c index c8f5b7d1736..4f4b8474b09 100644 --- a/src/backend/commands/copy.c +++ b/src/backend/commands/copy.c @@ -8,7 +8,7 @@ * * * IDENTIFICATION - * $PostgreSQL: pgsql/src/backend/commands/copy.c,v 1.309 2009/05/29 13:54:52 meskes Exp $ + * $PostgreSQL: pgsql/src/backend/commands/copy.c,v 1.310 2009/06/03 14:48:33 momjian Exp $ * *------------------------------------------------------------------------- */ @@ -175,7 +175,8 @@ typedef struct /* * These macros centralize code used to process line_buf and raw_buf buffers. * They are macros because they often do continue/break control and to avoid - * function call overhead in tight COPY loops. + * function call overhead in tight COPY loops. "((void) 0)" is used to silence + * compiler warnings. * * We must use "if (1)" because "do {} while(0)" overrides the continue/break * processing. See http://www.cit.gu.edu.au/~anthony/info/C/C.macros. -- GitLab